A ray of light is incident on a plane mirror | vedclass

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(B) When a plane mirror rotates by an angle $	heta$, the reflected ray rotates by an angle $2	heta$.Given angular acceleration $\alpha = 4\pi \, rad

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(B) When a plane mirror rotates by an angle $	heta$, the reflected ray rotates by an angle $2	heta$.Given angular acceleration $\alpha = 4\pi \, rad/s^2$ and time $t = \frac{1}{4} \, s$.The angle of rotation of the mirror is $	heta = \omega_0 t + \frac{1}{2} \alpha t^2$.Since the mirror starts from rest, $\omega_0 = 0$.$	heta = \frac{1}{2} 	imes (4\pi) 	imes (\frac{1}{4})^2 = 2\pi 	imes \frac{1}{16} = \frac{\pi}{8} \, radians$.Converting radians to degrees: $	heta = \frac{\pi}{8} 	imes \frac{180^\circ}{\pi} = 22.5^\circ$.The reflected ray rotates by $2	heta = 2 	imes 22.5^\circ = 45^\circ$.

$A$ ray of light is incident on a plane mirror at rest. The mirror starts turning at a uniform angular acceleration of $4\pi \, rad/s^2$. The reflected ray at the end of $\frac{1}{4} \, s$ must have turned through......$^o$

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