A ray is incident along ACB on a spherical mi | vedclass

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Question

(A) ray of light passing through the centre of curvature $(C)$ of a spherical mirror strikes the mirror surface normally (at an angle of $90^{\circ}$

Vedclass · Accepted Answer

Along the same path $BCA$

Vedclass · Answer

(A) ray of light passing through the centre of curvature $(C)$ of a spherical mirror strikes the mirror surface normally (at an angle of $90^{\circ}$ to the tangent at the point of incidence).According to the laws of reflection,when a ray strikes a surface normally,the angle of incidence $(i)$ is $0^{\circ}$.Therefore,the angle of reflection $(r)$ is also $0^{\circ}$.As a result,the ray reflects back along the same path,i.e.,$BCA$.

$A$ ray is incident along $ACB$ on a spherical mirror,where $C$ is the centre of curvature. In which direction will the ray be reflected?

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