A question paper has 2 parts,part A and part | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The number of ways to choose $8$ questions from $10$ in part $A$ is given by $C(10, 8)$.The number of ways to choose $5$ questions from $10$ in pa

Vedclass · Accepted Answer

$11340$

Vedclass · Answer

(D) The number of ways to choose $8$ questions from $10$ in part $A$ is given by $C(10, 8)$.The number of ways to choose $5$ questions from $10$ in part $B$ is given by $C(10, 5)$.Since these are independent selections,the total number of ways is the product of the two combinations:Total ways $= C(10, 8) 	imes C(10, 5)$$= \frac{10!}{8!2!} 	imes \frac{10!}{5!5!}$$= \frac{10 	imes 9}{2 	imes 1} 	imes \frac{10 	imes 9 	imes 8 	imes 7 	imes 6}{5 	imes 4 	imes 3 	imes 2 	imes 1}$$= 45 	imes 252 = 11340$.

$A$ question paper has $2$ parts,part $A$ and part $B$,each containing $10$ questions. If a student has to choose $8$ questions from part $A$ and $5$ questions from part $B$,in how many ways can the student choose the questions?

Similar Questions

In a plane,there are $10$ points,out of which $4$ are collinear. The number of triangles that can be formed by joining these points is:

The number of positive integral solutions of the equation $xyz = 3000$ is:

The value of $^{15}C_3 + ^{15}C_{13}$ is

How many $3$-digit odd numbers can be formed from the digits $1, 2, 3, 4, 5, 6$ when
$(i)$ repetition of digits is not allowed
(ii) repetition of digits is allowed?

If a man and his wife enter a bus in which five seats are vacant,then the number of different ways in which they can be seated is

Vedclass Test Series

Exam Paper Generator

Online Exam Module