A proton of mass 1.67times10^{-27}, kg and ch | vedclass

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Question

By using $r=\frac{m v \sin 	heta}{q B}$

$\Rightarrow r=\frac{1.67 	imes 15^{27} 	imes 2 	imes 10^{6} 	imes \sin 30^{\circ}}{1.6 	imes 10^{-19

Vedclass · Accepted Answer

A helix of radius $ \cong $ $0.1\, m$ and time period $2\pi 	imes10^{-7}\, s$.

Vedclass · Answer

By using $r=\frac{m v \sin 	heta}{q B}$

$\Rightarrow r=\frac{1.67 	imes 15^{27} 	imes 2 	imes 10^{6} 	imes \sin 30^{\circ}}{1.6 	imes 10^{-19} 	imes 0.104}$

$=0.1 m$

and it's time period

$T=\frac{2 \pi m}{q B}=\frac{2 	imes \pi 	imes 9.1 	imes 10^{-31}}{1.6 	imes 10^{-19} 	imes 0.104}$

$=2 \pi 	imes 10^{-7} \mathrm{sec}$

A proton of mass $1.67\times10^{-27}\, kg$ and charge $1.6\times10^{-19}\, C$ is projected with a speed of $2\times10^6\, m/s$ at an angle of $60^o$ to the $X-$ axis. If a uniform magnetic field of $0.104\, tesla$ is applied along the $Y-$ axis, the path of the proton is

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