$A$ projectile is thrown with a velocity of $50 \, ms^{-1}$ at an angle of $53^o$ with the horizontal. The equation of the trajectory is given by:

For a given velocity,a projectile has the same range $R$ for two angles of projection. If $t_1$ and $t_2$ are the times of flight in the two cases,then:

$A$ ball projected from the ground at an angle of $45^o$ just clears a wall in front. If the point of projection is $4 \, m$ from the foot of the wall and the ball strikes the ground at a distance of $6 \, m$ on the other side of the wall,the height of the wall is ........ $m$.

Two particles are simultaneously projected in opposite directions horizontally from a given point in space,where gravity $g$ is uniform. If $u_1$ and $u_2$ are their initial speeds,then the time $t$ after which their velocities are mutually perpendicular is given by

$A$ projectile object is thrown in the upward direction making an angle of $60^{\circ}$ with the horizontal with velocity of $140 \ m/s$. Then,the time after which its velocity makes an angle $30^{\circ}$ with the horizontal is (Take,$g=10 \ m/s^2$)

At what horizontal distance does a projectile reach its minimum kinetic energy?