A prism of refractive index sqrt{2} has a ref | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a prism,the refractive index $\mu$ is given by the formula: $\mu = \frac{\sin i}{\sin r}$.At the condition of minimum deviation,the angle of i

Vedclass · Accepted Answer

$45$

Vedclass · Answer

(A) For a prism,the refractive index $\mu$ is given by the formula: $\mu = \frac{\sin i}{\sin r}$.At the condition of minimum deviation,the angle of incidence $i$ is equal to the angle of emergence $e$,and the angle of refraction $r$ is equal to $A/2$,where $A$ is the refracting angle of the prism.Given: $\mu = \sqrt{2}$ and $A = 60^{\circ}$.Therefore,$r = \frac{A}{2} = \frac{60^{\circ}}{2} = 30^{\circ}$.Using Snell's law at the first surface: $\mu = \frac{\sin i}{\sin r}$.$\sqrt{2} = \frac{\sin i}{\sin 30^{\circ}}$.$\sin i = \sqrt{2} 	imes \sin 30^{\circ} = \sqrt{2} 	imes \frac{1}{2} = \frac{1}{\sqrt{2}}$.Thus,$i = \arcsin\left(\frac{1}{\sqrt{2}}ight) = 45^{\circ}$.

$A$ prism of refractive index $\sqrt{2}$ has a refracting angle of $60^{\circ}$. In order for a ray to suffer minimum deviation,it should be incident at an angle of.......$^{\circ}$.

Similar Questions

Vegetative propagation in mint occurs by

Two gases $A$ and $B$ having the same volume,effuse through an orifice in $30 \ min$ and $10 \ min$ respectively. The molar mass of $A$ is $162$. The molar mass of $B$ will be

$A$ conducting rod $PQ$ of length $L = 1.0\, m$ is moving with a uniform speed $v = 2\, m/s$ in a uniform magnetic field $B = 4.0\, T$ directed into the paper. $A$ capacitor of capacity $C = 10\, \mu F$ is connected as shown in the figure. Then:

The amplitude and the time period in a $S.H.M.$ are $0.5 \, cm$ and $0.4 \, s$ respectively. If the initial phase is $\pi / 2 \, rad$,then the equation of $S.H.M.$ will be

If $4\,P(A) = 6\,P(B) = 10\,P(A \cap B) = 1,$ then $P\left( \frac{B}{A} \right) = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module