A presbyopic patient has a near point of 30 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a person with myopia (far point limited),the corrective lens must form an image of an object at infinity at the patient's far point.Using the

Vedclass · Accepted Answer

$-2.5$

Vedclass · Answer

(C) For a person with myopia (far point limited),the corrective lens must form an image of an object at infinity at the patient's far point.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Here,the object distance $u = \infty$ and the image distance $v = -40 \, cm = -0.4 \, m$.Power $P = \frac{1}{f} = \frac{1}{v} - \frac{1}{u} = \frac{1}{-0.4} - \frac{1}{\infty}$.$P = -2.5 \, D$.

$A$ presbyopic patient has a near point of $30 \, cm$ and a far point of $40 \, cm$. The dioptric power of the corrective lens required for seeing distant objects is: (in $, D$)

Similar Questions

$A$ man who cannot see clearly beyond $5 \, m$ wants to see stars clearly. He should use a lens of focal length ....... $m$.

Identify the wrong description of the above figures.

If the distance of the far point for a myopia patient is doubled,the focal length of the lens required to cure it will become

$A$ man is suffering from colour blindness for green colour. To remove this defect,he should use goggles of

The image formed on the retina of the eye is proportional to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module