A potential divider circuit is shown in the f | vedclass

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(C) The circuit consists of several resistors connected in series across a $4 \ V$ $DC$ source.First,calculate the equivalent resistance $R_{eq}$ of t

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$0.5 \ V$

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(C) The circuit consists of several resistors connected in series across a $4 \ V$ $DC$ source.First,calculate the equivalent resistance $R_{eq}$ of the entire circuit:$R_{eq} = 3.3 \ k\Omega + 100 \ \Omega + 100 \ \Omega + 100 \ \Omega + 100 \ \Omega + 100 \ \Omega + 100 \ \Omega + 100 \ \Omega$$R_{eq} = 3300 \ \Omega + 700 \ \Omega = 4000 \ \Omega$Next,calculate the total current $i$ flowing through the circuit using Ohm's law:$i = \frac{V}{R_{eq}} = \frac{4 \ V}{4000 \ \Omega} = 10^{-3} \ A = 1 \ mA$The output voltage $V_0$ is measured across the last five $100 \ \Omega$ resistors (as shown in the figure,the arrow points to the junction after the first three resistors,and $V_0$ is across the remaining five resistors).Resistance across which $V_0$ is measured: $R_{out} = 5 	imes 100 \ \Omega = 500 \ \Omega$Therefore,$V_0 = i 	imes R_{out} = 1 	imes 10^{-3} \ A 	imes 500 \ \Omega = 0.5 \ V$.

$A$ potential divider circuit is shown in the figure. The output voltage $V_0$ is

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