A point source emits sound equally in all dir | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a point source in a non-absorbing medium,the intensity $I$ at a distance $r$ is given by $I = \frac{P}{4\pi r^2}$,where $P$ is the power of th

Vedclass · Accepted Answer

$25 : 9$

Vedclass · Answer

(C) For a point source in a non-absorbing medium,the intensity $I$ at a distance $r$ is given by $I = \frac{P}{4\pi r^2}$,where $P$ is the power of the source.Since $I \propto \frac{1}{r^2}$ and intensity is proportional to the square of the amplitude $(I \propto A^2)$,we have $A^2 \propto \frac{1}{r^2}$,which implies $A \propto \frac{1}{r}$.Therefore,the ratio of amplitudes at points $P$ and $Q$ is $\frac{A_P}{A_Q} = \frac{r_Q}{r_P}$.Given $r_P = 9 \ m$ and $r_Q = 25 \ m$,we get $\frac{A_P}{A_Q} = \frac{25}{9}$.Thus,the ratio is $25 : 9$.

$A$ point source emits sound equally in all directions in a non-absorbing medium. Two points $P$ and $Q$ are at a distance of $9 \ m$ and $25 \ m$ respectively from the source. The ratio of the amplitudes of the waves at $P$ and $Q$ is

Similar Questions

What is formed when $HCOOH$ reacts with concentrated $H_2SO_4$?

Which of the following reagents will convert propionic acid to $1-propanol$?

$A$ driver applies the brakes on seeing the red traffic signal $400 ~m$ ahead. At the time of applying the brakes,the vehicle was moving with $15 ~m/s$ and retarding at $0.3 ~m/s^2$. The distance covered by the vehicle from the traffic light $1$ minute after the application of brakes is (in $~m$)

For a reversible reaction $A \rightleftharpoons B$,which one of the following statements is wrong from the given energy profile diagram?

$\sqrt{12-\sqrt{68+48 \sqrt{2}}}$ is equal to :

Vedclass Test Series

Exam Paper Generator

Online Exam Module