(B) By definition,a circle is the collection of all points in a plane that are at a fixed distance from a fixed point. This fixed point is called the

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(B) By definition,a circle is the collection of all points in a plane that are at a fixed distance from a fixed point. This fixed point is called the centre of the circle. Since every point on the circle lies at this fixed distance (the radius) from the centre,the centre is equidistant from every point on the circle.

Class 9 Mathematics Circles Mix Examples - Circles

Easy

$A$ point located in the plane of a circle and which is equidistant from every point on the circle is called the ........ of the circle.

A
circumference
B
centre
C
diameter
D
radius

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Circles

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Mix Examples - Circles

$ABCD$ is a quadrilateral such that $A$ is the centre of the circle passing through $B, C$ and $D$. Prove that $\angle CBD + \angle CDB = \frac{1}{2} \angle BAD$.

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$AB$ and $AC$ are two chords of a circle with centre $P$. If the bisector of $\angle BAC$ passes through the centre $P$,prove that $AB = AC$.

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In a circle with centre $P$,$AB$ is a chord. If the length of a radius is $17\,cm$ and $AB = 30\,cm$,then find the distance of $AB$ from the centre $P$. (in $,cm$)

Medium

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Write True or False and justify your answer in each of the following: Two chords $AB$ and $CD$ of a circle are each at distances $4 \ cm$ from the centre. Then $AB = CD$.

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There is one and only one circle passing through all the vertices $A, B$ and $C$ of $\Delta ABC$. This circle is called the ............. of $\Delta ABC$.

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$A$ point located in the plane of a circle and which is equidistant from every point on the circle is called the ........ of the circle.

Similar Questions

$ABCD$ is a quadrilateral such that $A$ is the centre of the circle passing through $B, C$ and $D$. Prove that $\angle CBD + \angle CDB = \frac{1}{2} \angle BAD$.

$AB$ and $AC$ are two chords of a circle with centre $P$. If the bisector of $\angle BAC$ passes through the centre $P$,prove that $AB = AC$.

In a circle with centre $P$,$AB$ is a chord. If the length of a radius is $17\,cm$ and $AB = 30\,cm$,then find the distance of $AB$ from the centre $P$. (in $,cm$)

Write True or False and justify your answer in each of the following: Two chords $AB$ and $CD$ of a circle are each at distances $4 \ cm$ from the centre. Then $AB = CD$.

There is one and only one circle passing through all the vertices $A, B$ and $C$ of $\Delta ABC$. This circle is called the ............. of $\Delta ABC$.

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