A point Q lies on the perpendicular bisector | vedclass

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Question

(D) The electric field at a point on the equatorial line (perpendicular bisector) of an electric dipole is given by the formula:$E_{equatorial} = \fra

Vedclass · Accepted Answer

$p$ and $r^{-3}$

Vedclass · Answer

(D) The electric field at a point on the equatorial line (perpendicular bisector) of an electric dipole is given by the formula:$E_{equatorial} = \frac{1}{4\pi\epsilon_0} \frac{p}{r^3}$where $p$ is the dipole moment and $r$ is the distance from the center of the dipole.From this expression,it is clear that the electric field $E$ is directly proportional to the dipole moment $p$ $(E \propto p)$ and inversely proportional to the cube of the distance $r$ $(E \propto r^{-3})$.Therefore,the electric field at $Q$ is proportional to $p$ and $r^{-3}$.

$A$ point $Q$ lies on the perpendicular bisector of an electric dipole with dipole moment $p$. If the distance of $Q$ from the dipole is $r$ (where $r$ is much larger than the size of the dipole),then the electric field at $Q$ is proportional to:

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