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(B) The playground consists of a rectangle and two semi-circles on its smaller sides. Length of the rectangle $(l)$ $= 36 \, m$. Width of the rectangl

Vedclass · Accepted Answer

$1353.625$

Vedclass · Answer

(B) The playground consists of a rectangle and two semi-circles on its smaller sides. Length of the rectangle $(l)$ $= 36 \, m$. Width of the rectangle $(b)$ $= 24.5 \, m$. Diameter of each semi-circle $= 24.5 \, m$. Radius of each semi-circle $(r)$ $= \frac{24.5}{2} = 12.25 \, m$. Area of the playground $=$ Area of the rectangle $+$ Area of two semi-circles Area of the playground $= (l 	imes b) + \pi r^2$ Area of the playground $= (36 	imes 24.5) + \left( \frac{22}{7} 	imes 12.25 	imes 12.25 ight)$ Area of the playground $= 882 + \left( \frac{22}{7} 	imes 150.0625 ight)$ Area of the playground $= 882 + 471.625 = 1353.625 \, m^2$.

$A$ playground has the shape of a rectangle with two semi-circles on its smaller sides as diameters,added outside. If the sides of the rectangle are $36 \, m$ and $24.5 \, m$,then the area of the playground is ......... $m^2$ (use $\pi = \frac{22}{7}$).

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