A player caught a cricket ball of mass 150 g | vedclass

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Question

(D) Given:Mass of the ball,$m = 150 \ g = 0.15 \ kg$.Initial velocity,$u = 20 \ m/s$.Final velocity,$v = 0 \ m/s$ (since the ball is caught).Time take

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(D) Given:Mass of the ball,$m = 150 \ g = 0.15 \ kg$.Initial velocity,$u = 20 \ m/s$.Final velocity,$v = 0 \ m/s$ (since the ball is caught).Time taken,$t = 0.1 \ s$.According to Newton's Second Law of Motion,the force $F$ is given by the rate of change of momentum:$F = \frac{m(v - u)}{t}$Substituting the values:$F = \frac{0.15 	imes (0 - 20)}{0.1}$$F = \frac{0.15 	imes (-20)}{0.1}$$F = \frac{-3}{0.1} = -30 \ N$.The magnitude of the force exerted by the ball on the hand is $30 \ N$.

$A$ player caught a cricket ball of mass $150 \ g$ moving at a rate of $20 \ m/s$. If the catching process is completed in $0.1 \ s$,the force of the blow exerted by the ball on the hand of the player is equal to .......... $N$.

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