A plano-convex lens is made of refractive ind | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The lens maker's formula is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a plano-convex lens,one surface i

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(C) The lens maker's formula is given by: $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$.For a plano-convex lens,one surface is plane ($R_1 = 60 \ cm$,$R_2 = \infty$) or vice versa.Given: $\mu = 1.6$,$R_1 = 60 \ cm$,$R_2 = \infty$.Substituting the values into the formula:$\frac{1}{f} = (1.6 - 1) \left( \frac{1}{60} - \frac{1}{\infty} \right)$.Since $\frac{1}{\infty} = 0$,we have:$\frac{1}{f} = (0.6) \left( \frac{1}{60} \right) = \frac{0.6}{60} = \frac{6}{600} = \frac{1}{100}$.Therefore,$f = 100 \ cm$.

$A$ plano-convex lens is made of refractive index $1.6$. The radius of curvature of the curved surface is $60 \ cm$. The focal length of the lens is $..... \ cm$.

Similar Questions

An object is placed on the axis of a convex lens. Its image is formed $80 \, cm$ from the object. The magnification is $3$. The focal length of the lens is.....$cm$

The refractive index of a material of a plano-concave lens is $5/3$, and the radius of curvature is $0.3 \,m$. The focal length of the lens in air is (in $\,m$)

The radius of curvature of the convex surface of a thin plano-convex lens is $15 \ cm$ and the refractive index of its material is $1.6$. The power of the lens is

How is it convenient to obtain an image by a lens practically?

$A$ convex lens of focal length $f$ produces a real image $n$ times the size of the object. The image distance is

Vedclass Test Series

Exam Paper Generator

Online Exam Module