A person has to reach a certain place at a ce | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the distance to be covered be $d 	ext{ km}$ and the scheduled time be $t 	ext{ hours}$.Case $1$: Speed $= 4 	ext{ km/h}$,Time taken $= t +

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) Let the distance to be covered be $d 	ext{ km}$ and the scheduled time be $t 	ext{ hours}$.Case $1$: Speed $= 4 	ext{ km/h}$,Time taken $= t + \frac{15}{60} 	ext{ hours}$.Since $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$,we have $d = 4(t + \frac{1}{4}) = 4t + 1$.Case $2$: Speed $= 6 	ext{ km/h}$,Time taken $= t - \frac{10}{60} 	ext{ hours}$.Thus,$d = 6(t - \frac{1}{6}) = 6t - 1$.Equating the two expressions for $d$: $4t + 1 = 6t - 1 \implies 2t = 2 \implies t = 1 	ext{ hour}$.Substituting $t = 1$ in the first equation: $d = 4(1) + 1 = 5 	ext{ km}$.Alternatively,using the formula: $	ext{Distance} = \frac{S_1 	imes S_2}{|S_1 - S_2|} 	imes \Delta t = \frac{4 	imes 6}{6 - 4} 	imes \frac{15 + 10}{60} = \frac{24}{2} 	imes \frac{25}{60} = 12 	imes \frac{5}{12} = 5 	ext{ km}$.

$A$ person has to reach a certain place at a certain time. He finds that he will be $15 \text{ minutes}$ late if he walks at $4 \text{ km/h}$,and $10 \text{ minutes}$ earlier if he walks at $6 \text{ km/h}$. How far has he to walk? (in $\text{km}$)

Similar Questions

Train $A$ crosses a stationary Train $B$ in $50 \,s$ and a pole in $20 \,s$ with the same speed. The length of Train $A$ is $240 \,m$. What is the length of the stationary Train $B$ (in $m$)?

Two trains of equal length are running on parallel tracks in the same direction at the speeds of $46 \, km/h$ and $36 \, km/h$. The faster train passes the slower train in $36 \, seconds$. The length of each train is (in $m$):

In a race of $800\, m,$ $A$ can beat $B$ by $40\, m$. In a race of $500\, m,$ $B$ can beat $C$ by $5\, m$. In a race of $200\, m,$ $A$ will beat $C$ by? (in $m$)

$A$ man crosses a stationary bus in $18\, s$. The same bus crosses a pole in $4\, s$. What is the ratio of the speed of the bus to the speed of the man?

$A$ truck covers $224 \ km$ in $4 \ hours$. The average speed of a bike is $\frac{1}{4}$ of the average speed of the truck. How much distance will the bike cover in $7 \ hours$? (in $km$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module