A person cannot see distinctly at a distance | vedclass

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Question

(A) The person suffers from hypermetropia (farsightedness) as they cannot see objects closer than $1 \, m$ $(100 \, cm)$.To read a book at $u = -25 \,

Vedclass · Accepted Answer

$+ 3.0 \, D$

Vedclass · Answer

(A) The person suffers from hypermetropia (farsightedness) as they cannot see objects closer than $1 \, m$ $(100 \, cm)$.To read a book at $u = -25 \, cm$, the lens must form a virtual image at the person's near point, $v = -100 \, cm$.Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$.Substituting the values: $\frac{1}{f} = \frac{1}{-100} - \frac{1}{-25} = -\frac{1}{100} + \frac{1}{25} = \frac{-1 + 4}{100} = \frac{3}{100} \, cm^{-1}$.Since power $P = \frac{1}{f(	ext{in } meters)} = \frac{100}{f(	ext{in } cm)}$, we have $P = \frac{100}{100/3} = +3.0 \, D$.

$A$ person cannot see distinctly at a distance less than $1 \, m$. Calculate the power of the lens that he should use to read a book at a distance of $25 \, cm$.

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