A person bought a horse and a carriage for Rs | vedclass

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Question

Let, the price of horse be $₹ x$

$	herefore$ Price of carriage $=₹(20000-x)$

Now, according to the question,

$\frac{x 	imes 120}{100}+\frac

Vedclass · Accepted Answer

$8000$

Vedclass · Answer

Let, the price of horse be $₹ x$

$	herefore$ Price of carriage $=₹(20000-x)$

Now, according to the question,

$\frac{x 	imes 120}{100}+\frac{(20000-x) 	imes 90}{100}=20000\left(1+\frac{2}{100}ight)$

$\Rightarrow \frac{120 x}{100}+\frac{20000 	imes 90-90 x}{100}=20400$

$\Rightarrow 1.2 x+18000-0.9 x=20400$

$\Rightarrow 0.3 x=2400 \Rightarrow x=8000$

$\Rightarrow$ cost price of horse $=₹ 8000$

A person bought a horse and a carriage for $Rs.\,20000.$ Later, he sold the horse at $20 \%$ profit and the carriage at $10 \%$ loss. Thus, he gained $2 \%$ in the whole transaction. The cost price of the horse was (in $Rs.$)

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