(B) The magnitude of acceleration $a$ of a particle performing $SHM$ is given by $|a| = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is

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(B) The magnitude of acceleration $a$ of a particle performing $SHM$ is given by $|a| = \omega^2 y$,where $\omega$ is the angular frequency and $y$ is the displacement from the mean position.Given: $|a| = 20 \; m/s^2$ and $y = 5 \; m$.Substituting these values into the formula: $20 = \omega^2 (5)$.$\omega^2 = 4 \Rightarrow \omega = 2 \; rad/s$.The time period $T$ is given by $T = \frac{2\pi}{\omega}$.$T = \frac{2\pi}{2} = \pi \; s$.

Class 11 Physics Oscillations SHM of Simple Pendulum

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$A$ pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \; m/s^2$ at a distance of $5 \; m$ from the mean position. The time period of oscillation is

NEET 2018 All NEET

A
$2\pi \; s$
B
$\pi \; s$
C
$1 \; s$
D
$2 \; s$

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SHM of Simple Pendulum

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$A$ pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20 \; m/s^2$ at a distance of $5 \; m$ from the mean position. The time period of oscillation is

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