A pendulum clock keeps correct time at 0 ^oC. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g}}$.Taking the derivative,the fractional change in time period is $\fra

Vedclass · Accepted Answer

$\frac{1}{2} \alpha t 	imes 86400$

Vedclass · Answer

(D) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g}}$.Taking the derivative,the fractional change in time period is $\frac{\Delta T}{T} = \frac{1}{2} \frac{\Delta L}{L}$.Since $\Delta L = L \alpha \Delta 	heta$,where $\Delta 	heta = t$,we have $\frac{\Delta L}{L} = \alpha t$.Therefore,the fractional change in time is $\frac{\Delta T}{T} = \frac{1}{2} \alpha t$.This represents the time lost per second.Since there are $86400$ seconds in a day $(24 	imes 60 	imes 60 = 86400)$,the total time lost per day is given by $\Delta T_{day} = \frac{1}{2} \alpha t 	imes 86400$ seconds.

$A$ pendulum clock keeps correct time at $0\ ^oC$. The thermal coefficient of linear expansion of the material of the pendulum is $\alpha$. If the temperature rises to $t\ ^oC$,then the clock loses per day by (in seconds):

Similar Questions

In a reaction,$A + B \rightleftharpoons C + D$,$40 \%$ of $B$ has reacted at equilibrium,when $1 \ mole$ of $A$ was heated with $1 \ mole$ of $B$ in a $10 \ L$ closed vessel. The value of $K_C$ is

Which one of the following plots is correct for a first order reaction?

Flux $\phi$ (in weber) in a closed circuit of resistance $10\,\Omega$ varies with time $t$ (in sec) according to the equation $\phi = 6t^2 - 5t + 1$. What is the magnitude of the induced current at $t = 0.25\,s$ (in $,A$)?

The formula of sodium nitroprusside is:

The accessory glands of the human male reproductive system are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module