A particular station of All India Radio,New D | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The relationship between frequency $(
u)$,wavelength $(\lambda)$,and speed of light $(c)$ is given by the formula: $
u = \frac{c}{\lambda}$.Rear

Vedclass · Accepted Answer

$219.3 \, m$

Vedclass · Answer

(A) The relationship between frequency $(
u)$,wavelength $(\lambda)$,and speed of light $(c)$ is given by the formula: $
u = \frac{c}{\lambda}$.Rearranging the formula to solve for wavelength: $\lambda = \frac{c}{
u}$.Given: $c = 3.0 	imes 10^{8} \, m \, s^{-1}$ and $
u = 1,368 \, kHz = 1,368 	imes 10^{3} \, Hz$.Substituting the values: $\lambda = \frac{3.0 	imes 10^{8} \, m \, s^{-1}}{1,368 	imes 10^{3} \, s^{-1}}$.$\lambda = \frac{300,000,000}{1,368,000} \, m \approx 219.29 \, m$.Rounding to one decimal place,we get $\lambda \approx 219.3 \, m$.

List-$I$	List-$II$
$(1)$ $X$-rays	$(A)$ $\nu = 10^0 - 10^4 \ Hz$
$(2)$ Ultraviolet $(UV)$ rays	$(B)$ $\nu = 10^{10} \ Hz$
$(3)$ Long radio waves	$(C)$ $\nu = 10^{16} \ Hz$
$(4)$ Microwave	$(D)$ $\nu = 10^{18} \ Hz$

$A$ particular station of All India Radio,New Delhi,broadcasts on a frequency of $1,368 \, kHz$. The wavelength of the electromagnetic radiation emitted by the transmitter is : [speed of light $c = 3.0 \times 10^{8} \, m \, s^{-1}$]

Similar Questions

Match the following:

List-$I$ List-$II$

$(1)$ $X$-rays $(A)$ $\nu = 10^0 - 10^4 \ Hz$

$(2)$ Ultraviolet $(UV)$ rays $(B)$ $\nu = 10^{10} \ Hz$

$(3)$ Long radio waves $(C)$ $\nu = 10^{16} \ Hz$

$(4)$ Microwave $(D)$ $\nu = 10^{18} \ Hz$

Explain the production,characteristics,and uses of $X$-rays.

When radiation of $300 \ nm$ is shone on five metals,namely $Li, Mg, Ag, Cu,$ and $K$,the number of metals that show the photoelectric effect is:

What is the ratio of the energy of photons having wavelengths $2000 \ \mathring{A}$ and $4000 \ \mathring{A}$?

The energy of one mole of photons of radiation of frequency $2 \times 10^{12} \ Hz$ in $J \ mol^{-1}$ is $.....$ (Nearest integer) (Given: $h = 6.626 \times 10^{-34} \ Js$,$N_A = 6.022 \times 10^{23} \ mol^{-1}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module