A particle undergoes uniform circular motion. | vedclass

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(A) In uniform circular motion,the net force acting on the particle is the centripetal force,which is always directed towards the centre of the circle

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Centre of the circle

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(A) In uniform circular motion,the net force acting on the particle is the centripetal force,which is always directed towards the centre of the circle.The torque $\vec{	au}$ about any point is given by $\vec{	au} = \vec{r} 	imes \vec{F}$.Since the centripetal force $\vec{F}$ always passes through the centre of the circle,the position vector $\vec{r}$ relative to the centre is collinear with the force vector $\vec{F}$.Therefore,the torque about the centre is $\vec{	au} = 0$.According to the principle of conservation of angular momentum,if the net external torque about a point is zero,the angular momentum about that point remains conserved.Thus,the angular momentum of the particle is conserved about the centre of the circle.

$A$ particle undergoes uniform circular motion. About which point on the plane of the circle will the angular momentum of the particle remain conserved?

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