A particle of mass $m$ and charge $q$, accelerated by a potential difference $V$ enters a region of a uniform transverse magnetic field $B$. If $d$ is the thickness of the region of $B$, the angle $\theta$ through which the particle deviates from the initial direction on leaving the region is given by
A particle of mass $m$ and charge $q$, accelerated by a potential difference $V$ enters a region of a uniform transverse magnetic field $B$. If $d$ is the thickness of the region of $B$, the angle $\theta$ through which the particle deviates from the initial direction on leaving the region is given by
- A
$\sin \theta = Bd{\left( {\frac{q}{{2mV}}} \right)^{\frac{1}{2}}}$
- B
$\cos \theta = Bd{\left( {\frac{q}{{2mV}}} \right)^{\frac{1}{2}}}$
- C
$\tan \theta = Bd{\left( {\frac{q}{{2mV}}} \right)^{\frac{1}{2}}}$
- D
$\cot \theta = Bd{\left( {\frac{q}{{2mV}}} \right)^{\frac{1}{2}}}$
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