A particle of mass m moving with a speed v hi | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Particle $\mathrm{B}$ is a rest

$\mathrm{mv}+0=\mathrm{mv}_{1}+2 \mathrm{mv}_{2}$

$	herefore \mathrm{v}=\mathrm{v}_{1}+2 \mathrm{v}_{2}$

Vedclass · Accepted Answer

$\frac{{2\pi R}}{v}$

Vedclass · Answer

Particle $\mathrm{B}$ is a rest

$\mathrm{mv}+0=\mathrm{mv}_{1}+2 \mathrm{mv}_{2}$

$	herefore \mathrm{v}=\mathrm{v}_{1}+2 \mathrm{v}_{2}$        $...(i)$

$\frac{\mathrm{v}_{2}-\mathrm{v}_{1}}{\mathrm{v}+0}=1$

$\Rightarrow \mathrm{v}_{2}-\mathrm{v}_{1}=\mathrm{v}$          $...(ii)$

Adding $( i )$+$(ii)$

$3 v_{2}=2 v$

$	herefore \mathrm{v}_{2}=\frac{2}{3} \mathrm{v} \quad \mathrm{v}_{1}=\mathrm{v}_{2}-\mathrm{v}=\frac{-\mathrm{v}}{3}$

$\mathrm{Now},(\mathrm{ii})+(\mathrm{iv})$

$t=\frac{2 \pi r}{v_{2}-v_{1}}=\frac{2 \pi r}{\frac{2 v}{3}+\frac{v}{3}}$

$t=\frac{2 \pi r}{v}$

A particle of mass $m$ moving with a speed $v$ hits elastically another stationary particle of mass $2\ m$ in a fixed smooth horizontal circular tube of radius $R$. Find the time when the next collision will take place?

Similar Questions

Three particles $A, B$ & $C$ of equal mass move with speed $V$ as shown to strike at centroid of equilateral triangle after collision. $A$ comes to rest & $B$ retraces its path with speed $V$. speed of $C$ after collision is :-

A ball is thrown with a velocity of $6\, m/s$ vertically downwards from a height $H = 3.2\, m$ above a horizontal floor. If it rebounds back to same height then coefficient of restitution $e$ is $[g = 10\, m/s^2]$

A light particle moving horizontally with a speed $v_1$ strikes a very heavy block moving in the same direction with a speed $v_2$. The collision is elastic. After the collision, the velocity of particle is :-

A particle of mass $m$ strikes elastically on a wall with velocity $v$, at an angle of $60^{\circ}$ from the wall then magnitude of change in momentum of ball along the wall is

If a rubber ball falls from a height $h$ and rebounds upto the height of $h / 2$. The percentage loss of total energy of the initial system as well as velocity ball before it strikes the ground, respectively, are :