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(C) The effective current $i$ produced by a particle of charge $q$ moving with angular speed $\omega$ is given by $i = \frac{q}{T} = \frac{q\omega}{2\

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$q 	ext{ and } m$

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(C) The effective current $i$ produced by a particle of charge $q$ moving with angular speed $\omega$ is given by $i = \frac{q}{T} = \frac{q\omega}{2\pi}$.The area of the circular orbit is $A = \pi r^2$.The magnetic moment $M$ is defined as $M = iA = \left(\frac{q\omega}{2\pi}\right)(\pi r^2) = \frac{1}{2}q\omega r^2$.The angular momentum $L$ of the particle is $L = I\omega = (mr^2)\omega = m\omega r^2$.Taking the ratio of the magnitude of the magnetic moment to the angular momentum:$\frac{M}{L} = \frac{\frac{1}{2}q\omega r^2}{m\omega r^2} = \frac{q}{2m}$.Thus,the ratio $\frac{M}{L}$ depends only on the charge $q$ and the mass $m$ of the particle.

$A$ particle of charge $q$ and mass $m$ moves in a circular orbit of radius $r$ with angular speed $\omega$. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

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