A particle is thrown with a speed of $12\, m/s$ at an angle $60^o$ with the horizontal. The time interval between the moments when its speed is $10\, m/s$ is $(g = 10\, m/s^2)$.........$s$

  • A
    $1$
  • B
    $1.2$
  • C
    $1.4$
  • D
    $1.6$

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The angle of projection at which the horizontal range and maximum height of projectile are equal is

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A body is thrown at angle $30^{\circ}$ to the horizontal with the velocity of $30\; m / s$. After $1\;sec$, its velocity will be (in $m/s$) $\left(g=10\; m / s ^{2}\right)$

Given below are two statements : one is labelled as Assertion $A$ and the other is labelled as Reason $R$.

Assertion $A$ : When a body is projected at an angle $45^{\circ}$, it's range is maximum.

Reason $R$ : For maximum range, the value of $\sin 2 \theta$ should be equal to one.

In the light of the above statements, choose the correct answer from the options given below :

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A particle is thrown with a velocity of $u \,m / s$. It passes $A$ and $B$ as shown in figure at time $t_1=1 \,s$ and $t_2=3 \,s$. The value of $u$ is ....... $m / s$ $\left(g=10 \,m / s ^2\right)$