A particle is projected with an angle of projection $\theta$ to the horizontal line passing through the points $( P , Q )$ and $( Q , P )$ referred to horizontal and vertical axes (can be treated as $x$-axis and $y$-axis respectively).

The angle of projection can be given by

  • [AIIMS 2015]
  • A

    $\tan ^{-1}\left[\frac{ P ^2+ PQ + Q ^2}{ PQ }\right]$

  • B

    $\tan ^{-1}\left[\frac{ P ^2+ Q ^2- PQ }{ PQ }\right]$

  • C

    $\tan ^{-1}\left[\frac{ P ^2+ Q ^2}{2 PQ }\right]$

  • D

    $\sin ^{-1}\left[\frac{ P ^2+ Q ^2+ PQ }{2 PQ }\right]$

Similar Questions

The angle of projection at which the horizontal range and maximum height of projectile are equal is

If T is the total time of flight, $h$ is the maximum height $ \& R$ is the range for horizontal motion, the $x$ and $y$ co-ordinates of projectile motion and time $t$ are related as

      Column $-I$

    Angle of projection

    Column $-II$
  $A.$ $\theta \, = \,{45^o}$   $1.$ $\frac{{{K_h}}}{{{K_i}}} = \frac{1}{4}$
  $B.$ $\theta \, = \,{60^o}$   $2.$ $\frac{{g{T^2}}}{R} = 8$
  $C.$ $\theta \, = \,{30^o}$   $3.$ $\frac{R}{H} = 4\sqrt 3 $
  $D.$ $\theta \, = \,{\tan ^{ - 1}}\,4$   $4.$ $\frac{R}{H} = 4$

$K_i :$ initial kinetic energy

$K_h :$ kinetic energy at the highest point

A body is projected at such an angle that the horizontal range is three times the greatest height. The angle of projection is

  • [AIIMS 1998]

Aball is thrown from a point on ground at some angle of projection. At the same time a bird starts from a point directly above this point of projection at a height $h$ horizontally with speed $u$. Given that in its flight ball just touches the bird at one point. Find the distance on ground where ball strikes