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(B) The velocity of a particle moving in a circular path with constant speed $v$ is a vector quantity. Let the velocity at point $A$ be $\vec{v}_A$ an

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$v, 0$

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(B) The velocity of a particle moving in a circular path with constant speed $v$ is a vector quantity. Let the velocity at point $A$ be $\vec{v}_A$ and at point $B$ be $\vec{v}_B$. The magnitude of both is $v$.The magnitude of the change in velocity is given by $|\Delta \vec{v}| = |\vec{v}_B - \vec{v}_A| = 2v \sin(	heta/2)$,where $	heta = 60^{\circ}$.$|\Delta \vec{v}| = 2v \sin(60^{\circ}/2) = 2v \sin(30^{\circ}) = 2v 	imes (1/2) = v$.The magnitude of the velocity is constant $(v)$ throughout the motion. Therefore,the change in the magnitude of the velocity is $v - v = 0$.Thus,the magnitude of the change in velocity is $v$ and the change in the magnitude of velocity is $0$.

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