A particle is executing S.H.M. and its veloci | vedclass

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(B) Given the equation of motion: $v^2 + ax^2 = b$.Rearranging the equation to isolate $v^2$: $v^2 = b - ax^2$.Factor out $a$ from the right side: $v^

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$\frac{\sqrt{a}}{2 \pi}$

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(B) Given the equation of motion: $v^2 + ax^2 = b$.Rearranging the equation to isolate $v^2$: $v^2 = b - ax^2$.Factor out $a$ from the right side: $v^2 = a \left( \frac{b}{a} - x^2 \right)$.The standard equation for the velocity of a particle in $S.H.M.$ is $v^2 = \omega^2 (A^2 - x^2)$,where $\omega$ is the angular frequency and $A$ is the amplitude.Comparing the two equations,we get $\omega^2 = a$,which implies $\omega = \sqrt{a}$.The frequency of oscillation $f$ is given by $f = \frac{\omega}{2 \pi}$.Substituting the value of $\omega$: $f = \frac{\sqrt{a}}{2 \pi}$.

$A$ particle is executing $S.H.M.$ and its velocity $v$ is related to its position $x$ as $v^2 + ax^2 = b$,where $a$ and $b$ are positive constants. The frequency of oscillation of the particle is ..........

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