A particle is executing SHM with an amplitude | vedclass

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Question

(D) In $SHM$,a particle starts from the mean position,goes to the extreme position $(+A)$,returns to the mean position,goes to the other extreme posit

Vedclass · Accepted Answer

$4\,A$

Vedclass · Answer

(D) In $SHM$,a particle starts from the mean position,goes to the extreme position $(+A)$,returns to the mean position,goes to the other extreme position $(-A)$,and returns back to the mean position in one time period $(T)$.Distance travelled from mean to extreme $= A$.Distance travelled from extreme to mean $= A$.Distance travelled from mean to other extreme $= A$.Distance travelled from other extreme to mean $= A$.Total distance travelled in one time period $= A + A + A + A = 4\,A$.

$A$ particle is executing $SHM$ with an amplitude $A$. The distance travelled by the particle in one time period is

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