A particle $A$ has charge $+q$ and particle $B$ has charge $+ 4q$ with each of them having the same mass $m$. When allowed to fall from rest through same electrical potential difference, the ratio of their speed $V_A : V_B$ will be :-
A particle $A$ has charge $+q$ and particle $B$ has charge $+ 4q$ with each of them having the same mass $m$. When allowed to fall from rest through same electrical potential difference, the ratio of their speed $V_A : V_B$ will be :-
- A
$2 : 1$
- B
$1 : 2$
- C
$4 : 1$
- D
$1 : 4$
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- [KVPY 2018]