A two-digit number has 3 as its unit's digit, | vedclass

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(C) Let the two-digit number be represented as $10x + 3$,where $x$ is the tens digit and $3$ is the units digit.According to the problem,the sum of th

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$63$

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(C) Let the two-digit number be represented as $10x + 3$,where $x$ is the tens digit and $3$ is the units digit.According to the problem,the sum of the digits is $\frac{1}{7}$ of the number itself.So,$x + 3 = \frac{1}{7}(10x + 3)$.Multiplying both sides by $7$,we get $7(x + 3) = 10x + 3$.$7x + 21 = 10x + 3$.Rearranging the terms to solve for $x$: $21 - 3 = 10x - 7x$.$18 = 3x$.$x = 6$.Therefore,the required number is $10(6) + 3 = 63$.

$A$ two-digit number has $3$ as its unit's digit,and the sum of its digits is $\frac{1}{7}$ of the number itself. The number is:

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