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Question

(A) Let the original number be $x$.First,the number is decreased by $10 \%$,so the new number becomes $x - 0.10x = 0.90x$.Then,this number is increase

Vedclass · Accepted Answer

$1000$

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(A) Let the original number be $x$.First,the number is decreased by $10 \%$,so the new number becomes $x - 0.10x = 0.90x$.Then,this number is increased by $10 \%$,so the final number becomes $0.90x + 0.10(0.90x) = 0.90x + 0.09x = 0.99x$.According to the problem,the final number is $10$ less than the original number:$x - 0.99x = 10$$0.01x = 10$$x = \frac{10}{0.01} = 1000$.Therefore,the original number is $1000$.

$A$ number is decreased by $10 \%$ and then increased by $10 \%$. The number so obtained is $10$ less than the original number. What was the original number?

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