A normalvisioned man whose father was colour blind, marries a woman whose father was also colourblind. They have their first child as a daughter. What are the chances that this child would be colour blind ?
$1$
Zero percent
$0.25$
$0.5$
$A$ : The posssibility of a female becoming a haemophilic is extremely rare.
$R$ : Mother of such a female has to be carrier and father should be haemophilic
A woman with two genes for haemophillia and one gene for colourblindness on one of the $X$ chromosomes marries a normal man. How will the progeny be
In pedigree analysis, the square, blackened and horizontal lines represents
A man known to be victim of haemophilia marries a normal woman whose father was known to be a bleeder. Then it is expected that
Following characters are indicate
$(i)$ presence of sickle - shaped $RBC$
$(ii)$ Blood not clot, non stop bleeding
$(iii)$ The heterozygous female transmit the disease to sons.
$(iv)$ Both heterozygous parents transmit the disease to offspring