A non-metal M forms MCl_3,M_2O_5 and Mg_3M_2 | vedclass

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(C) The non-metal $M$ forms $MCl_3$,$M_2O_5$,and $Mg_3M_2$,which indicates it exhibits oxidation states of $+3$ and $+5$ and a valency of $3$ (as in $

Vedclass · Accepted Answer

Atomicity of non-metal is $4$

Vedclass · Answer

(C) The non-metal $M$ forms $MCl_3$,$M_2O_5$,and $Mg_3M_2$,which indicates it exhibits oxidation states of $+3$ and $+5$ and a valency of $3$ (as in $Mg_3M_2$).Since it does not form $MI_5$,it cannot expand its octet to show a covalency of $5$.This behavior is characteristic of nitrogen $(N)$,which belongs to the second period.Nitrogen has an atomicity of $2$ $(N_2)$,not $4$.Therefore,the statement 'Atomicity of non-metal is $4$' is incorrect.

$A$ non-metal $M$ forms $MCl_3$,$M_2O_5$ and $Mg_3M_2$ but does not form $MI_5$. Then the incorrect statement regarding non-metal $M$ is:

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