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(C) negatively charged particle placed in a uniform electric field $\vec{E}$ experiences an electrostatic force $\vec{F} = q\vec{E}$.Since the charge

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Decreases because the charge moves against the electric field

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(C) negatively charged particle placed in a uniform electric field $\vec{E}$ experiences an electrostatic force $\vec{F} = q\vec{E}$.Since the charge $q$ is negative,the force $\vec{F}$ acts in the direction opposite to the electric field $\vec{E}$.As the particle is released from rest,it accelerates in the direction of the force (opposite to the electric field).As the particle moves in the direction of the force,the work done by the electric field is positive.The change in electric potential energy $\Delta U$ is given by $\Delta U = -W_{field}$.Since the work done by the field is positive,the potential energy $U$ of the charge decreases.

$A$ negatively charged particle is released from rest in a uniform electric field. The electric potential energy of the charge:

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