A negative charged particle is released from rest in a uniform electric field. The electric potential energy of charge
A negative charged particle is released from rest in a uniform electric field. The electric potential energy of charge
- A
Remains constant because of uniform electric field
- B
Increases because charge moves opposite to electric field
- C
Decreases because charge moves against electric field
- D
Decreases because charge will move along electric field
Similar Questions
A parallel plate capacitor has plates with area $A$ and separation $d$. A battery charges the plates to a potential difference $V_0$. The battery is then disconnected and a dielectric slab of thickness $d$ is introduced. The ratio of energy stored in the capacitor before and after slab is introduced, is
A parallel plate capacitor has plates with area $A$ and separation $d$. A battery charges the plates to a potential difference $V_0$. The battery is then disconnected and a dielectric slab of thickness $d$ is introduced. The ratio of energy stored in the capacitor before and after slab is introduced, is
Find flux related to shaded face $BCGF$
Find flux related to shaded face $BCGF$
Two identical charged spherical drops each of capacitance $C$ merge to form a single drop. The resultant capacitance
Two identical charged spherical drops each of capacitance $C$ merge to form a single drop. The resultant capacitance
A spherical shell with an inner radius $'a'$ and an outer radius $'b'$ is made of conducting material. A point charge $+Q$ is placed at the centre of the spherical shell and a total charge $-q$ is placed on the shell. Final charge distribution on the surfaces as
A spherical shell with an inner radius $'a'$ and an outer radius $'b'$ is made of conducting material. A point charge $+Q$ is placed at the centre of the spherical shell and a total charge $-q$ is placed on the shell. Final charge distribution on the surfaces as
Two point charges $+8q$ and $-2q$ are located at $x = 0$ and $x = L$ respectively. The location of a point on the $x-$ axis at which net electric field due to these two point charges is zero, is
Two point charges $+8q$ and $-2q$ are located at $x = 0$ and $x = L$ respectively. The location of a point on the $x-$ axis at which net electric field due to these two point charges is zero, is