A motorcyclist travels a certain distance wit | vedclass

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(C) Let the distance between the starting point and the turning point be $D$.Time taken to travel the distance $D$ with speed $v_1 = 30\, m/s$ is $T_1

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(C) Let the distance between the starting point and the turning point be $D$.Time taken to travel the distance $D$ with speed $v_1 = 30\, m/s$ is $T_1 = D / 30$.Time taken to return the same distance $D$ with speed $v_2 = 20\, m/s$ is $T_2 = D / 20$.The total distance traveled is $D + D = 2D$.The total time taken is $T_1 + T_2 = D/30 + D/20 = (2D + 3D) / 60 = 5D / 60 = D / 12$.The average speed is defined as the total distance divided by the total time:Average Speed $= (2D) / (D / 12) = 2 	imes 12 = 24\, m/s$.

$A$ motorcyclist travels a certain distance with a uniform speed of $30\, m/s$ and immediately turns back and returns to the starting point with a uniform speed of $20\, m/s$. Then the average speed of the motorcycle is ..........$m/s$ :-

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