A motor bike running at $5\, m s ^{-1}$, picks up a velocity of $30\, m s ^{-1}$ in $5\, s$. Calculate $(i)$ acceleration $(ii)$ distance covered during acceleration.
A motor bike running at $5\, m s ^{-1}$, picks up a velocity of $30\, m s ^{-1}$ in $5\, s$. Calculate $(i)$ acceleration $(ii)$ distance covered during acceleration.
$u=5 m s ^{-1} ; v=30 m s ^{-1} ; t=5 s ; a=? ; S =?$
$(i)$ Applying $v=u+a t$
$30=5+a \times 5$
$5 a=25$ or $a=5 m s ^{-2}$
$(ii)$ Applying $v^{2}-u^{2}=2 a S$
$(30)^{2}-(5)^{2}=2 \times 5 \times S$
Or $875=10 \times S$
Or $S=87.5 m$
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