$A$ monoatomic gas molecule has

Internal energy of $n_1$ moles of hydrogen at temperature $T$ is equal to the internal energy of $n_2$ moles of helium at temperature $2T$. Then the ratio $n_1:n_2$ is: [Degree of freedom of $He = 3$,Degree of freedom of $H_2 = 5$]

If the degrees of freedom of a gas molecule is $6$,then the total internal energy of the gas molecule at a temperature of $47^{\circ} C$ (in $eV$) is (Boltzmann constant $= 1.38 \times 10^{-23} \ J \ K^{-1}$)

The kinetic energy per gram mole for a diatomic gas at room temperature is:

Write the degree of freedom for a diatomic rigid rotator.

The number of rotational degrees of freedom of a diatomic molecule is: