A mixture of ethyl iodide and n-propyl iodide | vedclass

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(B) The Wurtz reaction involves the coupling of alkyl halides in the presence of sodium metal to form higher alkanes.When a mixture of ethyl iodide $(

Vedclass · Accepted Answer

$n-$propane

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(B) The Wurtz reaction involves the coupling of alkyl halides in the presence of sodium metal to form higher alkanes.When a mixture of ethyl iodide $(C_2H_5I)$ and $n-$propyl iodide $(C_3H_7I)$ is used,the following products are formed:$1$. Self-coupling of ethyl iodide: $C_2H_5-C_2H_5$ ($n-$butane).$2$. Self-coupling of $n-$propyl iodide: $C_3H_7-C_3H_7$ ($n-$hexane).$3$. Cross-coupling of ethyl iodide and $n-$propyl iodide: $C_2H_5-C_3H_7$ ($n-$pentane).Therefore,$n-$propane is not formed in this reaction.

$A$ mixture of ethyl iodide and $n-$propyl iodide is subjected to Wurtz reaction. The hydrocarbon that will not be formed is

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