(B) According to Raoult's law,the total vapour pressure of the solution is given by $P = P_A^\circ x_A + P_B^\circ x_B$.Given:$P = 290 \, mm$$P_B^\cir

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) According to Raoult's law,the total vapour pressure of the solution is given by $P = P_A^\circ x_A + P_B^\circ x_B$.Given:$P = 290 \, mm$$P_B^\circ = 200 \, mm$ (vapour pressure of propyl alcohol)$x_A = 0.6$ (mole fraction of ethyl alcohol)$x_B = 1 - x_A = 1 - 0.6 = 0.4$ (mole fraction of propyl alcohol)Substituting the values in the equation:$290 = P_A^\circ \times 0.6 + 200 \times 0.4$$290 = P_A^\circ \times 0.6 + 80$$290 - 80 = P_A^\circ \times 0.6$$210 = P_A^\circ \times 0.6$$P_A^\circ = \frac{210}{0.6} = 350 \, mm$.

Class 12 Chemistry Solutions Lowering of vapour pressure

Medium

$A$ mixture of ethyl alcohol and propyl alcohol has a vapour pressure of $290 \, mm$ at $300 \, K$. The vapour pressure of propyl alcohol is $200 \, mm$. If the mole fraction of ethyl alcohol is $0.6$,its vapour pressure (in $mm$) at the same temperature will be:

AIEEE 2007 All AIEEE

A
$360$
B
$350$
C
$300$
D
$700$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Solutions

Subtopic

Lowering of vapour pressure

Previous Year

AIEEE 2007 Paper All AIEEE years →

An aqueous solution of $2\%$ non-volatile solute exerts a pressure of $1.004 \, bar$ at the normal boiling point of the solvent. The molar mass of the solute is $......... \, g/mol$.

Medium

View Solution

When $0.25 \text{ moles}$ of a non-volatile,non-ionizable solute was dissolved in $1 \text{ mole}$ of a solvent,the vapor pressure of the solution was $x\%$ of the vapor pressure of the pure solvent. What is $x$ (in $\%$)?

DifficultJEE MAIN 2026

View Solution

The vapor pressures of two liquids $P$ and $Q$ are $80 \ torr$ and $60 \ torr$,respectively. The total vapor pressure of a solution formed by mixing $3 \ moles$ of $P$ and $2 \ moles$ of $Q$ is .......... $torr$.

Medium

View Solution

Mass of Urea $(NH_2CONH_2)$ required to be dissolved in $1000 \ g$ of water to reduce the vapour pressure of water by $25 \ \%$ is $...... \ g$. (Nearest integer) Given: Molar mass of $N, C, O$ and $H$ are $14, 12, 16$ and $1 \ g \ mol^{-1}$ respectively.

MediumJEE MAIN 2023

View Solution

The vapor pressures of two pure liquids $(A)$ and $(B)$ are $100 \ Torr$ and $80 \ Torr$ respectively. What is the total vapor pressure of the solution formed by mixing $2 \ moles$ of $(A)$ and $3 \ moles$ of $(B)$ (in $Torr$)?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ mixture of ethyl alcohol and propyl alcohol has a vapour pressure of $290 \, mm$ at $300 \, K$. The vapour pressure of propyl alcohol is $200 \, mm$. If the mole fraction of ethyl alcohol is $0.6$,its vapour pressure (in $mm$) at the same temperature will be:

Similar Questions

An aqueous solution of $2\%$ non-volatile solute exerts a pressure of $1.004 \, bar$ at the normal boiling point of the solvent. The molar mass of the solute is $......... \, g/mol$.

When $0.25 \text{ moles}$ of a non-volatile,non-ionizable solute was dissolved in $1 \text{ mole}$ of a solvent,the vapor pressure of the solution was $x\%$ of the vapor pressure of the pure solvent. What is $x$ (in $\%$)?

The vapor pressures of two liquids $P$ and $Q$ are $80 \ torr$ and $60 \ torr$,respectively. The total vapor pressure of a solution formed by mixing $3 \ moles$ of $P$ and $2 \ moles$ of $Q$ is .......... $torr$.

Mass of Urea $(NH_2CONH_2)$ required to be dissolved in $1000 \ g$ of water to reduce the vapour pressure of water by $25 \ \%$ is $...... \ g$. (Nearest integer) Given: Molar mass of $N, C, O$ and $H$ are $14, 12, 16$ and $1 \ g \ mol^{-1}$ respectively.

The vapor pressures of two pure liquids $(A)$ and $(B)$ are $100 \ Torr$ and $80 \ Torr$ respectively. What is the total vapor pressure of the solution formed by mixing $2 \ moles$ of $(A)$ and $3 \ moles$ of $(B)$ (in $Torr$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module