A milliammeter of range 10 , mA has a coil of | vedclass

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(A) To convert a milliammeter into a voltmeter,a high resistance $R$ must be connected in series with the coil.Given:Range of milliammeter $(I_g)$ = $

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$999$

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(A) To convert a milliammeter into a voltmeter,a high resistance $R$ must be connected in series with the coil.Given:Range of milliammeter $(I_g)$ = $10 \, mA = 10 	imes 10^{-3} \, A = 0.01 \, A$.Resistance of the coil $(G)$ = $1 \, \Omega$.Required range of voltmeter $(V)$ = $10 \, V$.The formula for the series resistance $R$ is given by:$R = \frac{V}{I_g} - G$Substituting the values:$R = \frac{10}{0.01} - 1$$R = 1000 - 1 = 999 \, \Omega$.Therefore,a resistance of $999 \, \Omega$ must be connected in series.

$A$ milliammeter of range $10 \, mA$ has a coil of resistance $1 \, \Omega$. To use it as a voltmeter of range $10 \, V$,the resistance that must be connected in series with it will be ............. $\Omega$.

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