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(B) The rate of heat transfer $H$ is given by $H = \frac{K A \Delta T}{l}$.Given: $A = 9.0 \, cm^2 = 9.0 	imes 10^{-4} \, m^2$,$l = 0.54 \, m$,$\Delt

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$60$

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(B) The rate of heat transfer $H$ is given by $H = \frac{K A \Delta T}{l}$.Given: $A = 9.0 \, cm^2 = 9.0 	imes 10^{-4} \, m^2$,$l = 0.54 \, m$,$\Delta T = 100 \, ^\circ C - 0 \, ^\circ C = 100 \, K$.The rate of heat flow is also equal to the rate of melting of ice: $H = \frac{m L_f}{t}$,where $L_f = 334 \, J/g$ (latent heat of fusion of ice).$H = \frac{1 \, g 	imes 334 \, J/g}{33 \, s} \approx 10.12 \, W$.Equating the two expressions: $\frac{K 	imes 9.0 	imes 10^{-4} 	imes 100}{0.54} = \frac{334}{33}$.$K 	imes \frac{0.09}{0.54} = 10.12$.$K 	imes \frac{1}{6} = 10.12$.$K = 60.72 \, W m^{-1} K^{-1}$.Rounding to the nearest integer,$K = 60 \, W m^{-1} K^{-1}$.

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