A metallic ring connected to a rod oscillates | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When the metallic ring swings through the magnetic field,the magnetic flux linked with the ring changes. According to Faraday's law of electromagn

Vedclass · Accepted Answer

Come to rest very soon

Vedclass · Answer

(D) When the metallic ring swings through the magnetic field,the magnetic flux linked with the ring changes. According to Faraday's law of electromagnetic induction,an electromotive force $(EMF)$ is induced in the ring. Since the ring is metallic,this $EMF$ causes eddy currents to flow through it. According to Lenz's law,these eddy currents oppose the motion that produced them. This magnetic damping force acts against the motion of the pendulum,causing the mechanical energy of the pendulum to dissipate as heat due to the electrical resistance of the ring. Consequently,the pendulum will come to rest very soon.

$A$ metallic ring connected to a rod oscillates freely like a pendulum. If now a magnetic field is applied in a horizontal direction so that the pendulum now swings through the field,the pendulum will

Similar Questions

$A$ proton moves on a circular path with a constant angular speed. What is the correct relation between its magnetic moment $\vec M$ and angular momentum $\vec L$?

If the displacement $(x)$ and velocity $(v)$ of a particle executing simple harmonic motion are related through the expression $4 v^2 = 25 - x^2$,then the time period is

Velocity and acceleration vectors of a charged particle moving perpendicular to the direction of a magnetic field at a given instant of time are $\overrightarrow{v}=2 \hat{i}+c \hat{j}$ and $\overrightarrow{a}=3 \hat{i}+4 \hat{j}$ respectively. Then the value of $c$ is

Which one of the following is not observed in biodiversity hotspots?

Vedclass Test Series

Exam Paper Generator

Online Exam Module