A metallic block carrying current I is subjec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Since the block is metallic,the charge carriers are electrons. For a current $I$ along the positive $x$-axis,the electrons move along the negative

Vedclass · Accepted Answer

$evB\,\hat{k}$,$ABCD$

Vedclass · Answer

(A) Since the block is metallic,the charge carriers are electrons. For a current $I$ along the positive $x$-axis,the electrons move along the negative $x$-axis,i.e.,$\overrightarrow{v} = -v\hat{i}$.The magnetic field is along the $y$-axis,i.e.,$\overrightarrow{B} = B\hat{j}$.The Lorentz force is given by $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.Substituting the values,$\overrightarrow{F} = (-e)(-v\hat{i} 	imes B\hat{j}) = evB(\hat{i} 	imes \hat{j}) = evB\hat{k}$.Since the force on the electrons is in the positive $z$-direction,they accumulate on the face $ABCD$ (as per the coordinate system shown in the figure). The accumulation of negative charges on face $ABCD$ results in the lowering of its potential.

Similar Questions

If a proton, deuteron, and $\alpha$-particle are accelerated by the same potential difference and enter perpendicular to a magnetic field, then the ratio of their kinetic energies is:

$A$ proton of velocity $(3\hat i + 2\hat j) \, ms^{-1}$ enters a magnetic field of $(2\hat j + 3\hat k) \, T$. The acceleration produced in the proton is (charge to mass ratio of proton $= 0.96 \times 10^8 \, C/kg$)

Consider the mass spectrometer as shown in the figure. The electric field between the plates is $E \ V/m$,and the magnetic field in both the velocity selector and in the deflection chamber has magnitude $B$. Find the radius $r$ for a singly charged ion of mass $m$ in the deflection chamber.

$A$ charged particle with specific charge $S$ moves undeflected through a region of space containing mutually perpendicular uniform electric and magnetic fields $E$ and $B$. When the electric field is switched off,the particle will move in a circular path of radius:

Vedclass Test Series

Exam Paper Generator

Online Exam Module