A metal M forms an oxide having the formula M | vedclass

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(A) The metal $M$ is Aluminium $(Al)$.The oxide $Al_{2}O_{3}$ is amphoteric in nature,meaning it reacts with both acids and bases.Reaction with dilute

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Aluminium $(Al)$

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(A) The metal $M$ is Aluminium $(Al)$.The oxide $Al_{2}O_{3}$ is amphoteric in nature,meaning it reacts with both acids and bases.Reaction with dilute sulphuric acid:$Al_{2}O_{3}(s) + 3H_{2}SO_{4}(aq) \rightarrow Al_{2}(SO_{4})_{3}(aq) + 3H_{2}O(l)$Reaction with dilute sodium hydroxide solution:$Al_{2}O_{3}(s) + 2NaOH(aq) + 3H_{2}O(l) \rightarrow 2Na[Al(OH)_{4}](aq)$ (or Sodium aluminate $2NaAlO_{2} + H_{2}O$)

$A$ metal $M$ forms an oxide having the formula $M_{2}O_{3}$. It dissolves in both dilute sulphuric acid and dilute sodium hydroxide solution. Identify the metal and write the chemical equations for the reactions involved.

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$(a)$ Show the formation of $MgO$ by the transfer of electrons.
$(b)$ Name the cation and anion.
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