A mason constructs a wall of dimensions 270 , | vedclass

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(D) Volume of the wall $= 270 	imes 300 	imes 350 = 28,350,000 \,cm^3$.Since $\frac{1}{8}$ of the wall's volume is occupied by mortar,the volume occ

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$11200$

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(D) Volume of the wall $= 270 	imes 300 	imes 350 = 28,350,000 \,cm^3$.Since $\frac{1}{8}$ of the wall's volume is occupied by mortar,the volume occupied by the bricks is $\frac{7}{8}$ of the total volume.Volume occupied by bricks $= 28,350,000 	imes \frac{7}{8} = 24,806,250 \,cm^3$.Volume of one brick $= 22.5 	imes 11.25 	imes 8.75 = 2,214.84375 \,cm^3$.Number of bricks $= \frac{	ext{Volume occupied by bricks}}{	ext{Volume of one brick}} = \frac{24,806,250}{2,214.84375} = 11,200$.Therefore,the number of bricks used is $11,200$.

$A$ mason constructs a wall of dimensions $270 \,cm \times 300 \,cm \times 350 \,cm$ with bricks each of size $22.5 \,cm \times 11.25 \,cm \times 8.75 \,cm$. If $\frac{1}{8}$ of the total volume of the wall is occupied by mortar,find the number of bricks used to construct the wall.

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