A manufacturer sells an article to a wholesal | vedclass

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Question

(C) Let the cost price for the manufacturer be $₹ x$.$1$. The manufacturer sells it at $10 \%$ profit,so the selling price is $x 	imes (1 + \frac{10}

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(C) Let the cost price for the manufacturer be $₹ x$.$1$. The manufacturer sells it at $10 \%$ profit,so the selling price is $x 	imes (1 + \frac{10}{100}) = x 	imes \frac{110}{100}$.$2$. The wholesale dealer sells it at $20 \%$ profit,so the selling price is $(x 	imes \frac{110}{100}) 	imes (1 + \frac{20}{100}) = x 	imes \frac{110}{100} 	imes \frac{120}{100}$.$3$. The shopkeeper sells it at $15 \%$ loss for $₹ 56,100$,so the final equation is:$x 	imes \frac{110}{100} 	imes \frac{120}{100} 	imes \frac{85}{100} = 56,100$$4$. Simplifying the equation:$x 	imes \frac{11}{10} 	imes \frac{6}{5} 	imes \frac{17}{20} = 56,100$$x 	imes \frac{11 	imes 6 	imes 17}{1000} = 56,100$$x 	imes \frac{1122}{1000} = 56,100$$x = \frac{56,100 	imes 1000}{1122} = 50,000$Thus,the cost price for the manufacturer is $₹ 50,000$.

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