A man standing on a railway platform noticed | vedclass

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(C) Let the length of the train be $x\,m$.The time taken by the train to pass the man is $9\,s$.Therefore,the speed of the train is $v = \frac{x}{9}\,

Vedclass · Accepted Answer

$66$

Vedclass · Answer

(C) Let the length of the train be $x\,m$.The time taken by the train to pass the man is $9\,s$.Therefore,the speed of the train is $v = \frac{x}{9}\,m/s$.The time taken by the train to cross the platform is $21\,s$.When crossing the platform,the total distance covered is the sum of the length of the train and the length of the platform,which is $(x + 88)\,m$.Using the formula $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$,we have:$x + 88 = v 	imes 21$Substituting $v = \frac{x}{9}$:$x + 88 = \frac{x}{9} 	imes 21$$x + 88 = \frac{7x}{3}$$3(x + 88) = 7x$$3x + 264 = 7x$$4x = 264$$x = 66\,m$.Thus,the length of the train is $66\,m$.

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