A man of blood group-$A$, marries a woman of blood group-$B$, both of them are heterozygous for blood group, chances of their first child having blood group $AB$ will be
A man of blood group-$A$, marries a woman of blood group-$B$, both of them are heterozygous for blood group, chances of their first child having blood group $AB$ will be
- A
$25\, \%$
- B
$50\, \%$
- C
$75 \,\%$
- D
$100\, \%$
Similar Questions
A child with mother of $O$ blood group and father of $A$ blood group, will have the following blood group.
A child with mother of $O$ blood group and father of $A$ blood group, will have the following blood group.
Mother and father both have blood group $‘A’$. They have two children one with blood group $‘O’$ and second one with blood group $‘A’$. They have
Mother and father both have blood group $‘A’$. They have two children one with blood group $‘O’$ and second one with blood group $‘A’$. They have
- [AIIMS 2009]
When dominant and recessive alleles express themselves together, it is called
When dominant and recessive alleles express themselves together, it is called
- [AIPMT 2001]
Definitions / Explanation : Co-dominance
Definitions / Explanation : Co-dominance
The blood of $AB$ group donor can be transfused to a person with the blood group
The blood of $AB$ group donor can be transfused to a person with the blood group