$A$ man can swim with a speed of $4.0 \; km/h$ in still water. How long does he take to cross a river $1.0 \; km$ wide if the river flows steadily at $3.0 \; km/h$ and he makes his strokes normal to the river current? How far down the river does he go when he reaches the other bank?

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(A) Speed of the man in still water,$v_m = 4.0 \; km/h$.
Width of the river,$d = 1.0 \; km$.
Since the man swims normal to the river current,his velocity component across the river is $v_m = 4.0 \; km/h$.
Time taken to cross the river,$t = \frac{d}{v_m} = \frac{1.0 \; km}{4.0 \; km/h} = 0.25 \; h$.
Converting to minutes,$t = 0.25 \times 60 = 15 \; min$.
Speed of the river,$v_r = 3.0 \; km/h$.
The distance covered down the river (drift) is $x = v_r \times t = 3.0 \; km/h \times 0.25 \; h = 0.75 \; km$.
Converting to meters,$x = 0.75 \times 1000 = 750 \; m$.

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